Problem: The equation x+xβ2β=4 has:
Answer Choices:
A. 2 real roots
B. 1 real and 1 imaginary root
C. 2 imaginary roots
D. no roots
E. 1 real root and 1 extraneous root
Solution:
xβ2β=4βx,xβ2=16β8x+x2,
0=x2β9x+18=(xβ6)(xβ3);β΄x=6,x=3.
A check is obtained only with x=3.