Problem:
The sum to infinity of 71β+722β+731β+742β+β¦ is:
Answer Choices:
A. 51β
B. 241β
C. 485β
D. 161β
E. none of these answers
Solution:
Rearrange the terms:
s1βs2βsβ=71β+731β+β―=722β+742β+β―=s1β+s2βββ=1β491β71ββ=1β491β492ββ=487β+482βββ=487β=482β=489β=163ββ
Answer: Eβ.