Problem: The values of y which will satisfy the equations
2x2+6x+5y+12x+y+3=0=0 may be found by solving:
Answer Choices:
A. y2+14y−7=0
B. y2+8y+1=0
C. y2+10y−7=0
D. y2+y−12=0
E. none of the above equations
Solution:
Solve the second equation for x, substitute into the first equation and simplify:
x=−2y+3,2(−2y+3)2+6(−2y+3)+5y+1=0;∴y2+10y−7=0.