Problem:
When simplified and expressed with negative exponents, the expression (x+y)β1(xβ1+yβ1) is equal to:
Answer Choices:
A. xβ2+2xβ1yβ1+yβ2
B. xβ2+2β1xβ1yβ1+yβ2
C. xβ1yβ1
D. xβ2+yβ2
E. xβ1yβ11β
Solution:
(x+y)β1(xβ1+yβ1)β=x+y1β(x1β+y1β)=x+y1β(xyyβ+xyxβ)=x+y1β(xyx+yβ)=(x+y)β1ββ
xy(x+y)ββ=xy1β=xβ1yβ1ββ