Problem: The apothem of a square having its area numerically equal to its perimeter is compared with the apothem of an equilateral triangle having its area numerically equal to its perimeter. The first apothem will be:
Answer Choices:
A. equal to the second
B. 34β times the second
C. 3β2β times the second
D. 3β2ββ times the second
E. indeterminately related to the second
Solution:
Let s1β be the side of the square, a1β its apothem; then s12β=4s1β and since 2a1β=s1β, we have 4a12β=8a1β or a1β=2. Let s2β be the side of the equilateral triangle, h its altitude and a2β its apothem; then s22β3β/4=3s2β. Since h=3a2β, and s2β=2h/3β=6a2β/3β, we have (36a22β/3)3β/4=3β 6a2β/3β, and a2β=2=a1β.