Problem: If two poles 20β²β² and 80β²β² high are 100β²β² apart, then the height of the intersection of the lines joining the top of each pole to the foot of the opposite pole is:
Answer Choices:
A. 50β²β²
B. 40β²β²
C. 16β²β²
D. 60β²β²
E. none of these
Solution:
x1β=201β+801β;
β΄x=16 (inches);
or
10020β=yxβ,y=5x
and 10080β=100βyxβ
=100β5xxβ;
x=16 (inches)