Problem: The roots of the equation x2β2x=0 can be obtained graphically by finding the abscissas of the points of intersection of each of the following pairs of equations except the pair:
Answer Choices:
A. y=x2,y=2x
B. y=x2β2x,y=0
C. y=x,y=xβ2
D. y=x2β2x+1,y=1
E. y=x2β1,y=2xβ1
Solution:
(x2β2x=0)β(x2=2x)ββ(x2β2x+1=1)β(x2β1=2xβ1).β
β΄(C) is the correct choice.