Problem: ((x3+1)2(x+1)2(x2βx+1)2β)2β
[(x3β1)2(xβ1)2(x2+x+1)2β]2 equals:
Answer Choices:
A. (x+1)4
B. (x3+1)4
C. 1
D. [(x3+1)(x3β1)]2
E. [(x3β1)2]2
Solution:
Since x3+1=(x+1)(x2βx+1) and
x3β1=(xβ1)(x2+x+1)
the given expression, when simplified, is 1 (with suitable restrictions on the value of x ).