Problem: If x+yxy=a,x+zxz=b and y+zyz=c, where a,b, and c are other than zero, then x equals:
Answer Choices:
A. ab+ac+bcabc
B. ab+bc+ac2abc
C. ab+ac−bc2abc
D. ab+bc−ac2abc
E. ac+bc−ab2abc
Solution:
Inverting each of the expressions, we have the set of equations:
y1+x1=a1,z1+x1=b1,y1+z1=c1.∴x1−z1=a1−c1,x1+z1=b1;∴x2=a1+b1−c1.∴x=ac+bc−ab2abc.