Problem: The function x2+px+qx^{2}+p x+qx2+px+q with ppp and qqq greater than zero has its minimum value when:
Answer Choices:
A. x=βpx=-px=βp
B. x=p2x=\dfrac{p}{2}x=2pβ
C. x=β2px=-2 px=β2p
D. x=p24qx=\dfrac{p^{2}}{4 q}x=4qp2β
E. x=βp2x=\dfrac{-p}{2}x=2βpβ Solution:
The minimum value of the function is at the turning point of the graph where x=βp/2x=-p / 2x=βp/2.