Problem: Two equal parallel chords are drawn 8 8 8 8
Answer Choices:
A. 21 1 3 Ο β 32 3 2 1 3 1 β Ο β 3 2 3 β
B. 32 3 + 21 1 3 Ο 3 2 3 β + 2 1 3 1 β Ο
C. 32 3 + 42 2 3 Ο 3 2 3 β + 4 2 3 2 β Ο
D. 16 3 + 42 2 3 Ο 1 6 3 β + 4 2 3 2 β Ο
E. 42 2 3 Ο 4 2 3 2 β Ο Solution:
By symmetry, the required area is 4 ( T + S ) 4 ( T + S )
T = 1 2 4 β
4 3 = 8 3 , S = ( 30 / 360 ) β
Ο 8 2 = 5 1 3 Ο β΄ A = 32 3 + 21 1 3 Ο . β T = 2 1 β 4 β
4 3 β = 8 3 β , S = ( 3 0 / 3 6 0 ) β
Ο 8 2 = 5 3 1 β Ο β΄ A = 3 2 3 β + 2 1 3 1 β Ο . β
