Problem: In the set of equations zx=y2x,2z=2⋅4x,x+y+z=16, the integral roots in the order x,y,z are:
Answer Choices:
A. 3,4,9
B. 9,−5,12
C. 12,−5,9
D. 4,3,9
E. 4,9,3
Solution:
From equation (1) z=y2.
From equation (2) 2z=22x+1,z=2x+1;
∴x=2z−1=2y2−1
From equation (3) 2y2−1+y+y2=16. This equation has one integral root y=3. ∴x=4,y=3,z=9