Problem: When simplified, (xβ1+yβ1)β1\left(x^{-1}+y^{-1}\right)^{-1}(xβ1+yβ1)β1 is equal to:
Answer Choices:
A. x+yx+yx+y
B. xyx+y\dfrac{x y}{x+y}x+yxyβ
C. xyx yxy
D. 1xy\dfrac{1}{x y}xy1β
E. x+yxy\dfrac{x+y}{x y}xyx+yβ Solution:
(xβ1+yβ1)β1=1(1/x)+(1/y)=xyx+y\left(x^{-1}+y^{-1}\right)^{-1}=\dfrac{1}{(1 / x)+(1 / y)}=\dfrac{x y}{x+y} (xβ1+yβ1)β1=(1/x)+(1/y)1β=x+yxyβ