Problem: If m=caba−bm=\dfrac{c a b}{a-b}m=a−bcab, then bbb equals:
Answer Choices:
A. m(a−b)ca\dfrac{m(a-b)}{c a}cam(a−b)
B. cab−ma−m\dfrac{c a b-m a}{-m}−mcab−ma
C. 11+c\dfrac{1}{1+c}1+c1
D. mam+ca\dfrac{m a}{m+c a}m+cama
E. m+cama\dfrac{m+c a}{m a}mam+ca Solution:
ma−mb=cab,ma=b(m+ca);∴b=ma/(m+ca)m a-m b=c a b, \quad m a=b(m+c a) ; \quad \therefore b=m a /(m+c a)ma−mb=cab,ma=b(m+ca);∴b=ma/(m+ca).