Problem: The equation x+10ββx+10β6β=5 has
Answer Choices:
A. an extraneous root between β5 and β1
B. an extraneous root between β10 and β6
C. a real root between 20 and 25
D. two real roots
E. two extraneous roots
Solution:
Multiply both sides of the equation by x+10β.
x+10β6=5x+10β,x2β17xβ234=0,x=26 or β9.
β9 fails to check, i.e., it is an extraneous root.