Problem: Charles has 5q+15q+15q+1 quarters and Richard has q+5q+5q+5 quarters. The difference in their money in dimes is
Answer Choices:
A. 10(q−1)10(q-1)10(q−1)
B. 2/5(4q−4)2 / 5(4q-4)2/5(4q−4)
C. 2/5(q−1)2 / 5(q-1)2/5(q−1)
D. 5/2(q−1)5 / 2(q-1)5/2(q−1)
E. none of these Solution:
52[(5q+1)−(q+5)]=52(4q−4)=10(q−1)\dfrac{5}{2}[(5 q+1)-(q+5)]=\dfrac{5}{2}(4 q-4)=10(q-1)25[(5q+1)−(q+5)]=25(4q−4)=10(q−1).