Problem: The two roots of the equation a(b−c)x2+b(c−a)x+c(a−b)=0 are 1 and:
Answer Choices:
A. a(b−c)b(c−a)
B. c(a−b)a(b−c)
C. b(c−a)a(b−c)
D. a(b−c)c(a−b)
E. b(c−a)c(a−b)
Solution:
The product of the roots is c(a−b)/a(b−c). Since one root is 1, the other is the fraction shown.