Problem: The value of 3a+b\dfrac{3}{a+b}a+b3 when a=4a=4a=4 and b=−4b=-4b=−4 is:
Answer Choices:
A. 333
B. 3/83 / 83/8
C. 000
D. any finite number
E. meaninglessmeaninglessmeaningless Solution:
When a=4a=4a=4 and b=−4,a+b=0b=-4, a+b=0b=−4,a+b=0. Therefore, the expression becomes meaningless for these values.