Problem: Two numbers whose sum is 6 and the absolute value of whose difference is 888 are roots of the equation:
Answer Choices:
A. x2−6x+7=0x^{2}-6 x+7=0x2−6x+7=0
B. x2−6x−7=0x^{2}-6 x-7=0x2−6x−7=0
C. x2+6x−8=0x^{2}+6 x-8=0x2+6x−8=0
D. x2−6x+8=0x^{2}-6 x+8=0x2−6x+8=0
E. x2+6x−7=0x^{2}+6 x-7=0x2+6x−7=0 Solution:
The numbers are 7 and -1 ; the required equation is, therefore,
x2−6x+7=0.x^{2}-6 x+7=0 . x2−6x+7=0.