Problem: The smaller angle between the hands of a clock at 12:2512: 2512:25 p.m. is:
Answer Choices:
A. 132∘30′132^{\circ} 30^{\prime}132∘30′
B. 137∘30′137^{\circ} 30^{\prime}137∘30′
C. 150∘150^{\circ}150∘
D. 137∘32′137^{\circ} 32^{\prime}137∘32′
E. 137∘137^{\circ}137∘ Solution:
150∘−2560⋅30∘=13712∘=137∘30′150^{\circ}-\dfrac{25}{60} \cdot 30^{\circ}=137 \frac{1}{2}{ }^{\circ}=137^{\circ} 30^{\prime}150∘−6025⋅30∘=13721∘=137∘30′.