Problem: In our number system the base is ten. If the base were changed to four you would count as follows: 1,2,3,10,11,12,13,20,21,22,23,30,β¦ The twentieth number would be:
Answer Choices:
A. 20
B. 38
C. 44
D. 104
E. 110
Solution:
20=1β
42+1β
41+0β
40;β΄ the required number is 1104β;
or
20Γ·4 yields 5 and remainder 0;
5Γ·4 yields 1 and remainder 1;
β΄2010β becomes 1104β.