Problem: The equation x+4ββxβ3β+1=0 has:
Answer Choices:
A. no root
B. one real root
C. one real root and one imaginary root
D. two imaginary roots
E. two real roots
Solution:
x+4β=xβ3ββ1;β΄x+4=xβ3β2xβ3β+1; β΄3=βxβ3β. This is impossible since the left side is positive while the right side is negative.