Problem: The roots of the equation ax2+bx+c=0a x^{2}+b x+c=0ax2+bx+c=0 will be reciprocal if:
Answer Choices:
A. a=ba=ba=b
B. a=bca=b ca=bc
C. c=ac=ac=a
D. c=bc=bc=b
E. c=abc=a bc=ab Solution:
For reciprocal roots, the product of the roots c/a=1.∴c=ac / a=1 . \quad \therefore c=ac/a=1.∴c=a.