Problem: The angle formed by the hands of a clock at 2:152: 152:15 is:
Answer Choices:
A. 30∘30^{\circ}30∘ B. 2712∘27 \frac{1}{2}^{\circ}2721∘ C. 15712∘157 \frac{1}{2}^{\circ}15721∘ D. 17212∘172 \frac{1}{2}^{\circ}17221∘ E. none of these Solution:
90−(60∘+14⋅30)∘=2212∘90-\left(60^{\circ}+\dfrac{1}{4} \cdot 30\right)^{\circ}=22 \dfrac{1}{2}^{\circ}90−(60∘+41⋅30)∘=2221∘;
∴(E)\therefore(\mathrm{E})∴(E) is correct.