Problem: A rational number between 2\sqrt{2}2β and 3\sqrt{3}3β is:
Answer Choices:
A. 2+32\dfrac{\sqrt{2}+\sqrt{3}}{2}22β+3ββ
B. 2β 32\dfrac{\sqrt{2} \cdot \sqrt{3}}{2}22ββ 3ββ
C. 1.51.51.5
D. 1.81.81.8
E. 1.41.41.4 Solution:
(A) and (B) are irrational. Of the remaining choices only (C) is between 2\sqrt{2}2β and 3\sqrt{3}3β.