Problem: Circle O has diameters AB and CD perpendicular to each other. AM is any chord intersecting CD at P. Then APβ
AM is equal to:
Answer Choices:
A. AOβ
OB
B. AOβ
AB
C. CPβ
CD
D. CPβ
PD
E. COβ
OP
Solution:
ABM is a right triangle. By similar triangles, AP/AB=AO/AM. β΄APβ
AM=AOβ
AB.