Problem: The sum of the reciprocals of the roots of the equation x2+px+q=0x^{2}+p x+q=0x2+px+q=0 is:
Answer Choices:
A. −p/q-p / q−p/q
B. q/pq / pq/p
C. p/qp / qp/q
D. −q/p-q / p−q/p
E. pqp qpq Solution:
1r+1s=r+srs=−pq\dfrac{1}{r}+\dfrac{1}{s}=\dfrac{r+s}{r s}=\dfrac{-p}{q}r1+s1=rsr+s=q−p.