Problem: In circle O,G is a moving point on diameter AB. AAβ² is drawn perpendicular to AB and equal to AG.BBβ² is drawn perpendicular to AB, on the same side of diameter AB as AAβ², and equal to BG. Let Oβ² be the midpoint of Aβ²Bβ². Then, as G moves from A to B, point Oβ²:
Answer Choices:
A. moves on a straight line parallel to AB
B. remains stationary
C. moves on a straight line perpendicular to AB
D. moves in a small circle intersecting the given circle
E. follows a path which is neither a circle nor a straight line
Solution:
Aβ²ABBβ² is a trapezoid. Its median OOβ² is perpendicular to AB.
OOβ²=21β(AAβ²+BBβ²)=21β(AG+BG)=21βAB.
β΄Oβ² is a fixed distance from O on the perpendicular to AB, and therefore the point Oβ² is stationary.