Problem: The area of a circle inscribed in an equilateral triangle is 48Ο. The perimeter of this triangle is:
Answer Choices:
A. 723β
B. 483β
C. 36
D. 24
E. 72
Solution:
For the inscribed circle
r=h/3=s3β/6.p=3s=63βr=(63β)(43β)=72.
( A=Οr2,r=48β=43β.)