Problem: The value of xβyxβyx-y^{x-y}xβyxβy when x=2x=2x=2 and y=β2y=-2y=β2 is:
Answer Choices:
A. β18-18β18
B. β14-14β14
C. 141414
D. 181818
E. 256256256 Solution:
2β(β2)4=2β16=β142-(-2)^{4}=2-16=-142β(β2)4=2β16=β14.