Problem: The value of [2−3(2−3)−1]−1\left[2-3(2-3)^{-1}\right]^{-1}[2−3(2−3)−1]−1 is:
Answer Choices:
A. 555
B. −5-5−5
C. 1/51 / 51/5
D. −1/5-1 / 5−1/5
E. 5/35 / 35/3 Solution:
(2−3(−1)−1)−1=5−1=15\left(2-3(-1)^{-1}\right)^{-1}=5^{-1}=\dfrac{1}{5} (2−3(−1)−1)−1=5−1=51