Problem: If x is positive and logxβ₯log2+1/2logx, then:
Answer Choices:
A. x has no minimum or maximum value
B. the maximum value of x is 1
C. the minimum value of x is 1
D. the maximum value of x is 4
E. the minimum value of x is 4
Solution:
1/2logxβ₯log2
logxβ₯log4
xβ₯4
or
logxβ₯log2xβ
xβ₯2xβ
xββ₯2
xβ₯4