Problem: The base of an isosceles triangle is 2β. The medians to the legs intersect each other at right angles. The area of the triangle is:
Answer Choices:
A. 1.5
B. 2
C. 2.5
D. 3.5
E. 4
Solution:
x2+x2=2β΄x=1β΄DF=22ββ
But
AEADβ=32ββ΄EGDFβ=32ββ΄EG=432βββ΄altitude CDF=232ββ
β΄A=21ββ
2ββ
232ββ=23β
or
x2+x2=2β΄x=1
β΄y2=1+41ββ΄y=25βββ΄BC=5β