Problem: A harmonic progression is a sequence of numbers such that their reciprocals are in arithmetic progression. Let Snβ represent the sum of the first n terms of the harmonic progression; for example, S3β represents the sum of the first three terms. If the first three terms of a harmonic progression are 3,4,6, then:
Answer Choices:
A. S4β=20
B. S4β=25
C. S5β=49
D. S6β=49
E. S2β=1/2S4β
Solution:
31β,41β,161β,121β,0 with d=β121β
therefore the terms of the H.P. are 3,4,6,12 only β΄S4β=25