Problem: Given the polynomial a0xn+a1xn−1+…+an−1x+an, where n is a positive integer or zero, and a0 is a positive integer. The remaining a's are integers or zero. Set h=n+a0+∣a1∣+∣a2∣+…+∣an∣. The number of polynomials with h=3 is:
Answer Choices:
A. 3
B. 5
C. 6
D. 7
E. 9
Solution:
For h=3 we can have 1x2,1x1+1,1x1−1,2x1,3x0