Problem: An altitude h of a triangle is increased by a length m. How much must be taken from the corresponding base b so that the area of the new triangle is one-half that of the original triangle?
Answer Choices:
A. h+mbm
B. 2(h+m)bh
C. m+hb(2m+h)
D. 2m+hb(m+h)
E. 2(h+m)b(2m+h)
Solution:
Let d be the amount taken from the base b. Then 21( b−d)(h+m)=21⋅21bh
Solving for d, we obtain d=2(h+m)b(2m+h)