Problem: If the graphs of 2y+x+3=0 and 3y+ax+2=0 are to meet at right angles, the value of a is:
Answer Choices:
A. Β±32β
B. β32β
C. β23β
D. 6
E. β6
Solution:
Let m1β be the slope of the line 2y+x+3=0, and m2β, the slope of the line 3y+ax+2=0 For perpendicularity m1βm2β=β1
therefore (β21β)(β3aβ)=β1 therefore a=β6