Problem: Let the two base angles of a triangle be A and B, with B larger than A. The altitude to the base divides the vertex angle C into two parts, C1 and C2, with C2 adjacent to side a. Then:
Answer Choices:
A. C1+C2=A+B
B. C1−C2=B−A
C. C1−C2=A−B
D. C1+C2=B−A
E. C1−C2=A+B
Solution:
Since B+C2=90∘ and A+C1=90∘,B+C2 =A+C1∴C1−C2=B−A