Problem: Let a(L)b represent the operation on two numbers, a and b, which selects the larger of the two numbers, with a(L)a=a. Let a(s)b represent the operation which selects the smaller of the two numbers, with a(s)a=a.
Which of the following three rules is (are) correct?
(1) a(L)b=b(L)a
(2) a(L)(b(L)c)=(a(L)b)(L)c
(3) a(s)(b(L)c)=(a(s)b)(L)(a(s)c)
Answer Choices:
A. (1) only
B. (2) only
C. (1) and (2) only
D. (1) and (3) only
E. all three
Solution:
The correctness of rule (1) is obvious. To establish rule (2) take three numbers n1β,n2β,n3β such that n1β>n2β>n3β. First select the larger of n2β and n3β, which is n2β; then select the larger of n1β and n2β, which is n1β. We thus obtain n1β from the left side of the rule. From the right side of the rule we also obtain n1β as follows: First select the larger of n1β and n2β, which is n1β, then select the larger of n1β and n3β, which is n1β.
For rule 3 we proceed as follows: For the left side we first select the larger of n2β and r3β (this is n2β ). then select the smaller of n1β and n2β (this is ag. in n2β ). For the right side, select the smaller of n and n2β (this is n2β ) then select the smaller of n1β and n3β (this is n3β ), and. finally. select the larger of n2β and n3β (this is n2β ).