Problem: Which of the following sets of x-values satisfy the inequality 2x2+x<6?
Answer Choices:
A. β2<x<23β
B. x>23β or x<β2
C. x<23β
D. 23β<x<2
E. x<β2
Solution:
2x2+x<6,x2+2xβ<3,x2+2xβ+161β<3+161β, (x+41β)2<1649β,β£β£β£β£β£βx+41ββ£β£β£β£β£β<47β, that is. x+41β<47β and x+41β>β47ββ΄x<23β and x>β2.