Problem: Which one of the following points is not on the graph of y=x+1xβ?
Answer Choices:
A. (0,0)
B. (β21β,β1)
C. (21β,31β)
D. (β1,1)
E. (β2,2)
Solution:
Since x+1xβ is not defined when the denominator is zero, and since the denominator x+1 equals zero when x=β1, any point whose abscissa is β1 , such as (β1,1) can not be on the graph.