Problem: The expression x2βy2βz2+2yz+x+yβz has:
Answer Choices:
A. no linear factor with integer coefficients and integer exponents
B. the factor βx+y+z
C. the factor xβyβz+1
D. the factor x+yβz+1
E. the factor xβy+z+1
Solution:
x2βy2βz2+2yz+x+yβz=x2β(y2β2yz+z2)+x+yβz=x2β(yβz)2+x+yβz =(x+yβz)(xβy+z)+x+yβz=(x+yβz)(xβy+z+1)