Problem: If (7+43)x2+(2+3)x−2=0, the larger root minus the smaller root is:
Answer Choices:
A. −2+33
B. 2−3
C. 6+33
D. 6−33
E. 33+2
Solution:
Let the roots be r and s with r≧s.
∴r−s=7+43(2+3)2+8(7+43). Since 7+43=(2+3)2,r−s=2+33=6−33