Problem: The sum of the reciprocals of the roots of the equation ax2+bx+c=0 is:
Answer Choices:
A. a1β+b1β
B. βbcβ
C. cbβ
D. βbaβ
E. βcbβ
Solution:
Let the roots be r and s; then r+s=βb/a and rs=c/a
β΄r1β+s1β=rsr+sβ=c/aβb/aβ=βb/c,cξ =0,aξ =0