Problem: Let s1β be the sum of the first n terms of the arithmetic sequence 8,12,β― and let s2β be the sum of the first n terms of the arithmetic sequence 17,19,β―. Then s1β=s2β for:
Answer Choices:
A. no value of n
B. one value of n
C. two values of n
D. four values of n
E. a value of n greater than four
Solution:
s1β=2nβ(16+(nβ1)4),s2β=2nβ(34+(nβ1)2). But s1β=s2β implies 2nβ(12+4n)=2nβ(32+2n)
β΄12+4n=32+2n,n=10 so that choice ( B ) is correct.