Problem: Let O be an interior point of triangle ABC and let s1β=OA+OB+OC. If s2β=AB+BC+CA, then
Answer Choices:
A. for every triangle s1β>21βs2β,s1ββ¦s2β
B. for every triangle s1ββ§21βs2β,s1β<s2β
C. for every triangle s1β>21βs2β,s1β<s2β
D. for every triangle s1ββ§21βs2β,s1ββ¦s2β
E. (E) neither (A) nor (B) nor (C) nor (D) applies to every triangle
Solution:
OA+OCOC+OBOB+OA2s1βs1ββ>AC>BC>AB>s2β>21βs2ββOB+OCOC+OAOA+OB2s1βs1ββ<AB+AC<BC+AB<AC+BC<2s2β<s2βββ