Problem: The area of a rectangle remains unchanged when it is made 221β inches longer and 32β inch narrower, or when it is made 221β inches shorter and 34β inch wider. Its area, in square inches, is:
Answer Choices:
A. 30
B. 80/3
C. 24
D. 45/2
E. 20
Solution:
If l and w represent the dimensions of the rectangle, then (l+25β)(wβ32β)=(lβ25β)(w+34β)=lw β΄l=215β and w=38β, and the area is 20.