Problem: If x is such that x1β<2 and x1β>β3, then:
Answer Choices:
A. β31β<x<21β
B. β21β<x<3
C. x>21β
D. x>21β or β31β<x<0
E. x>21β or x<β31β
Solution:
Method I. Let y=x1β. Then (a) For y>0, when y<2,y1β>21ββ΄x>21β.
(b) For y<0, when y>β3,βy<3,βy1β>31β,y1β<β3 β΄x<β31β.
Method II. Let y=x1ββ΄xy=1; the graph is the two-branched hyperbola shown. At the point x=21β,y=2. When y<2,x is to right of 21β, that is, x>21β. At the point x=β31β,y=β3. When y>β3,x is to the left of β31β, that is, x<β31β.