Problem: If a number N,Nξ =0, diminished by four times its reciprocal, equals a given real constant R, then, for this given R, the sum of all such possible values of N is:
Answer Choices:
A. R1β
B. R
C. 4
D. 41β
E. βR
Solution:
Nβ4β
N1β=Rβ΄N2βRNβ4=0. Let the values of N satisfying this equation be N1β and N2β. Therefore, N1β+N2β=R. For example, if R=3, then N1β,N2β are 4,β1 and the sum of 4 and β1 equals 3 .