Problem: Find the sum of the digits of all the numerals in the sequence 1,2,3,4,β―,10000.
Answer Choices:
A. 180001
B. 154756
C. 45001
D. 154755
E. 270001
Solution:
Omit 10,000 for the moment. In the sequence 0000,0001,0002,0003,β―,9999 each digit appears the same number of times. There are (10,000)(4) digits in all, each digit appearing 4,000 times. The sum of the digits is 4,000(0+1+2+β―+9)= 4,000(45)=180,000. Now add the 1 in 10,000 to get 180,001 .